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Zion Williamson's Contract With Jordan Brand is Largest Rookie Shoe Deal in NBA History

LOS ANGELES, CALIFORNIA - JULY 10: Zion Williamson poses with his ESPY for Best College Athlete at The 2019 ESPYs at Microsoft Theater on July 10, 2019 in Los Angeles, California. (Photo by Rich Fury/Getty Images)
Rich Fury/Getty Images

New Orleans Pelicans rookie Zion Williamson has been the talk of the NBA offseason. After being selected first overall in the NBA Draft, Williamson reached an agreement with Jordan Brand on a shoe endorsement deal.

To say Williamson secured the bag is a massive understatement.

According to Action Network's Darren Rovell, Williamson's contract with Jordan Brand is for five-years and worth $75 million, which is the largest for a rookie in NBA history.

LeBron James previously held the record when signing with Nike in 2003, where he earned an annual salary of $12.4 million over seven years. Williamson blows the annual wage out of the water with $15 million in the next five years.

After Williamson announced his decision through his Instagram account, NBA insider Adrian Wojnarowski revealed that several shoe companies offered larger sums of money than Jordan Brand.

Despite the ridiculous amount of money left on the table, Williamson chose to wear the logo of his favorite player growing up.

Even with the discount, Williamson owns the richest rookie shoe deal in the history of the NBA, which is mind-boggling.